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covedweller
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 Posted: Thu Nov 16, 2006 12:58 pm Post subject: [K] Third Eye Blind, Losing A Whole Year: a word problem |
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K. Song #5: Total the days of each year, as if the mention of each counts as a seperate loss. Take into account that there'd be two leap years. Days in bed never count as a loss. Each mention gains you an additional week. All combined, how many days are lost?
5. Third Eye Blind - Losing A Whole Year |
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ForeverMourn
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| Posted: Thu Nov 16, 2006 1:14 pm Post subject: |
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| Scalare wrote: | The answer posted for K has to be right.
K. Song #5:
http://www.lyricsfreak.com/t/third+eye+blind/losing+a+whole+year_20136740.html is pretty good, but the last "losing a whole year isn't mentioned in the song itself..
Total the days of each year, as if the mention of each counts as a seperate loss. -> 365 x 8 (number of times "Losing a whole year") = 2920
Take into account that there'd be two leap years. -> +2 = 2922.
Days in bed never count as a loss. Each mention gains you an additional week. = 3 weeks in bed. (3x7=21)
All combined, how many days are lost?
2922 - 21 = 2901. |
One Theory.
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ForeverMourn
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| Posted: Thu Nov 16, 2006 1:19 pm Post subject: |
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| Quote: | Scalare wrote:
Actually, if the days in bed aren't lost but instead give you a week instead we shouldn't count them towards the loss...
We might have to subtract 3 first and then add 21 to it... So that'd put us at 2898.
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This could be.
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Captious
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| Posted: Thu Nov 16, 2006 1:20 pm Post subject: |
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| The other theory that's big counts each of the 3 times as one day that wasn't lost in addition to giving it a week and thus puts it at 2898. |
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covedweller
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| Posted: Thu Nov 16, 2006 1:22 pm Post subject: |
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Deagol did some math that came up with a 310-933-xxxx #.
2898 works into that solution.
To get the last 4 digits of this possible #, we only need tweak C & D. Those are known and possible letters. |
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Scalare
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| Posted: Thu Nov 16, 2006 1:29 pm Post subject: |
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| covedweller wrote: | Deagol did some math that came up with a 310-933-xxxx #.
2898 works into that solution.
To get the last 4 digits of this possible #, we only need tweak C & D. Those are known and possible letters. |
You'd also need to tweak E and F to get possible answers to the last 4 digits..
With C=9
And D=3
You get the number : 3109335901
Please note that I also did : E=10.
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Killthesmiley
The Order of Denderah
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| Posted: Thu Nov 16, 2006 1:32 pm Post subject: |
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SCORE
CONGRATS
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kelly
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Scalare
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| Posted: Thu Nov 16, 2006 1:33 pm Post subject: |
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| Killthesmiley wrote: | SCORE
CONGRATS |
huh?
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Killthesmiley
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| Posted: Thu Nov 16, 2006 1:34 pm Post subject: |
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thats the number
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kelly
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Scalare
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| Posted: Thu Nov 16, 2006 1:34 pm Post subject: |
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| Killthesmiley wrote: | | thats the number |
Elaborate.. what did it say?? was there a voicemail?
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ForeverMourn
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Killthesmiley
The Order of Denderah
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| Posted: Thu Nov 16, 2006 2:34 pm Post subject: |
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thats what I said earlier about making so many threads about this one puzzle
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kelly
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ForeverMourn
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| Posted: Thu Nov 16, 2006 2:36 pm Post subject: |
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Hmph. Me too.
^_^
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Killthesmiley
The Order of Denderah
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| Posted: Thu Nov 16, 2006 2:39 pm Post subject: |
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tiger!!!
or any other Mod!!!
come in here plz and clean ths mess up!!!!!
this is aboslute choas
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kelly
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